Faking all instances of every parent

Hi there,

I've recently started using Typemock in an attempt to demo it at our company. I've read the documentation and have looked through at least half a dozen existing threads, but can't seem to find an answer to my exact problem.

I have a class C that derives from B, that itself derives from A. The instance of C is what I need to test and therefore needs to be real. But as C derives from B (and indirectly A), I need those two classes completely faked automatically when I create an instance of C.

See below:

class A
{
	protected int methodA()
	{
		return 1;
	}
}

class B : A
{
	protected int methodB()
	{
		return 5;
	}
}

class C : B
{
	public int methodC()
	{
		return methodA() * methodB();
	}
}

class Test
{
	public Test()
	{
		A fake_A = Isolate.Fake.AllInstances<A>(Members.ReturnRecursiveFakes, ConstructorWillBe.Ignored);
		Isolate.NonPublic.WhenCalled(fake_A, "methodA").DoInstead((MethodCallContext ctx) =>
			{
				return 2;
			}
		);
		
		B fake_B = Isolate.Fake.AllInstances<B>(Members.ReturnRecursiveFakes, ConstructorWillBe.Ignored);
		Isolate.NonPublic.WhenCalled(fake_B, "methodB").DoInstead((MethodCallContext ctx) =>
			{
				return 10;
			}
		);

		C c = new C(); // Would expect A and B to be faked automatically since I've faked all instances above. 
		int method_c_val = c.methodC(); // I get back 5, but what I need returned is 20.
	}
}

One of the threads I've already looked at is this one, but the answer in there points to an address which is no longer available:

https://www.typemock.com/answers/11613/mocking-all-instances-of-a-base-class